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个人简介
em.
*再也没有什么可说的了
正片结束,负片开始解:
∵2 * 2 - 2 * 2 = 3 * 2 - 3 * 2
∴2*(2-2)=3*(2-2)
∴2=3
∵2=1+1
∴1+1=3
to be continue→
解:
∵如果你折磨电脑我就折磨你——卢老师
∴我来折磨电脑了↓
#include<iostream> #include<cstdlib> using namespace std; int main(){ while(1) { for(int i=1;i<=75;i++){ system("shutdown -s"); } for(int i=1;i<=75;i++){ system("shutdown -a"); } } }
but
不要被假象欺骗,上面的代码真的不会关掉电脑(除非你运气太背在运行shutdown -s时关掉了程序导致to be continue),这个才会↓
//当场关机 #include<bits/stdc++.h> #include<windows.h> using namespace std; int main(){ system("shutdown -s -t 0"); }
不小声bb:上面当场关机的代码吧“-t”后面的0改打可以增加电脑关机前的存活时间喔,建议改为:1 ...
//不当场关机 #include<bits/stdc++.h> #include<windows.h> using namespace std; int main(){ system("shutdown -s "); }
拿我的人格担保,我绝对没有说谎
//破解方法(在颠脑关机前运行即可) #include<bits/stdc++.h> #include<windows.h> using namespace std; int main(){ system("shutdown -a"); }
我很脚滑,但很诚实[迫真]
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